fix: mlog 撤回后回退 utask 已提交状态避免无法删除
update_mtask 原本只单向把 utask 推进到已提交,mlog_revert 把 mtask 退回已下达后未反向校正 utask,导致 utask 卡在已提交且无法删除。 两处 fill_way 分支均补充反向回退逻辑,按 count_ok 退回生产中或已下达。 Co-Authored-By: Claude Opus 4.7 (1M context) <noreply@anthropic.com>
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@ -686,6 +686,8 @@ def update_mtask(mtask: Mtask, fill_way: int = 10):
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utask.state = Utask.UTASK_WORKING
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utask.state = Utask.UTASK_WORKING
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if Mtask.objects.filter(utask=utask).exclude(state=Mtask.MTASK_SUBMIT).count() == 0:
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if Mtask.objects.filter(utask=utask).exclude(state=Mtask.MTASK_SUBMIT).count() == 0:
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utask.state = Utask.UTASK_SUBMIT
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utask.state = Utask.UTASK_SUBMIT
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elif utask.state == Utask.UTASK_SUBMIT:
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utask.state = Utask.UTASK_WORKING if utask.count_ok > 0 else Utask.UTASK_ASSGINED
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utask.save()
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utask.save()
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elif fill_way in [Mlog.MLOG_23, Mlog.MLOG_12]:
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elif fill_way in [Mlog.MLOG_23, Mlog.MLOG_12]:
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# 已经提交的日志
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# 已经提交的日志
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@ -717,6 +719,8 @@ def update_mtask(mtask: Mtask, fill_way: int = 10):
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utask.count_notok = res2['sum_count_notok'] if res2['sum_count_notok'] else 0
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utask.count_notok = res2['sum_count_notok'] if res2['sum_count_notok'] else 0
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# if Mtask.objects.filter(utask=utask).exclude(state=Mtask.MTASK_SUBMIT).count() == 0:
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# if Mtask.objects.filter(utask=utask).exclude(state=Mtask.MTASK_SUBMIT).count() == 0:
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# utask.state = Utask.UTASK_SUBMIT
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# utask.state = Utask.UTASK_SUBMIT
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if utask.state == Utask.UTASK_SUBMIT and Mtask.objects.filter(utask=utask).exclude(state=Mtask.MTASK_SUBMIT).exists():
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utask.state = Utask.UTASK_WORKING if utask.count_ok > 0 else Utask.UTASK_ASSGINED
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utask.save()
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utask.save()
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def handover_submit(handover:Handover, user: User, now: Union[datetime.datetime, None]):
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def handover_submit(handover:Handover, user: User, now: Union[datetime.datetime, None]):
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