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feat: 添加has_perm方法typing

This commit is contained in:
caoqianming 2023-10-11 15:34:27 +08:00
parent e41710e438
commit 1cc632b35b
1 changed files with 5 additions and 1 deletions
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6
apps/utils/permission.py
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@ -3,6 +3,7 @@ from rest_framework.permissions import BasePermission
from apps.utils.queryset import get_child_queryset2 from apps.utils.queryset import get_child_queryset2
from apps.system.models import DataFilter, Dept, Permission, PostRole, UserPost, User from apps.system.models import DataFilter, Dept, Permission, PostRole, UserPost, User
from django.db.models.query import QuerySet from django.db.models.query import QuerySet
from typing import List
ALL_PERMS = [ ALL_PERMS = [
@ -41,7 +42,10 @@ def get_user_perms_map(user):
return user_perms_map return user_perms_map
def has_perm(user: User, perm_codes): def has_perm(user: User, perm_codes: List[str]):
"""
返回用户是否具有给定权限列表中的权限
"""
user_perms_map = cache.get(f'perms_{user.id}', None) user_perms_map = cache.get(f'perms_{user.id}', None)
if user_perms_map is None: if user_perms_map is None:
user_perms_map = get_user_perms_map(user) user_perms_map = get_user_perms_map(user)